Assuming your cooking a packaged refrigerated/frozen meal, just follow the instructions.
Tip: NEVER use 'popcorn' mode to cook popcorn (unless the package says so)
Answer:
(c) A list of words
Explanation:
<em>First let's format the code properly</em>
fin = open('words.txt')
for line in fin:
word = line.strip()
print(word)
<em>Second, let's explain each line of the code</em>
Line 1:
The open() function is a built-in function that takes in, as argument, the name of a file, and returns a file object that can be used to read the file.
In this case, the name of the file is <em>words.txt. </em>Therefore, the variable <em>fin </em>is a file object which contains the content of the file - <em>words.txt</em>
Line 2:
The <em>for </em>loop is used to read in each line of the content of the file object (fin).
Line 3:
Each line of the contents is stripped to remove any trailing and leading white spaces by calling on the <em>strip()</em> function. The result of the strip is stored in the variable <em>word.</em>
Line 4:
The content of word at each of the cycles of the loop is printed to the console.
Therefore, the overall output of the program is a list of words where each word represents a line in the target file (words.txt)
Answer:
JavaScripts Object Notation (JSON)
Explanation:
Answer:
sentence = "hello wow a stores good"
same_letter_count = 0
sentence_list = sentence.split()
for s in sentence_list:
if s[0] == s[-1]:
same_letter_count += 1
print(same_letter_count)
Explanation:
*The code is in Python.
Initialize the sentence with a string
Initialize the same_letter_count as 0
Split the sentence using split method and set it to the sentence_list
Create a for loop that iterates through the sentence_list. If the first and last of the letters of a string are same, increment the same_letter_count by 1
When the loop is done, print the same_letter_count