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svp [43]
3 years ago
14

Unit 6: Lesson 2 - Coding Activity 1 AP Computer science

Computers and Technology
1 answer:
sladkih [1.3K]3 years ago
8 0

The complete program is to define a boolean method that returns true if all elements of an array are negative, or return false, if otherwise

The method in java, where comments are used to explain each line is as follows:

//This defines the method

public static boolean chkNegative (double[] myArr) {

   //This initializes a boolean variable

   boolean isNeg = true;

   //This iterates through the array

   for (int i = 0; i < myArr.length; i++) {

     //If the array element is 0 or positive

     if (myArr[i] >= 0) {

         //Then the boolean variable is set to false

       isNeg = false;

       //And the loop is exited

       break;

     }

   }

   //This returns true or false

   return isNeg;

 }

Read more about boolean methods at:

brainly.com/question/18318709

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Write an assembly language program with a loop and indexed addressing that calculates the sum of all the gaps between successive
PSYCHO15rus [73]

Answer:

Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.

;Include Irvine32.inc file used with link library for 32 bit applications

.386

.model flat,stdcall

.stack 4096

ExitProcess proto,dwExitCode:dword

INCLUDE Irvine32.inc

.data

myArray DWORD 0,2,5,9,10

arrSize = ($-myArray)/TYPE myArray

gapArr DWORD arrSize-1 DUP(?)

sum DWORD ?

.code

main PROC

;Call the procedure

call Clrscr

;Initialize ESI pointer

mov esi, 0

mov ecx, arrSize

dec ecx

L1:

mov eax, myArray[esi+4]

sub eax, myArray[esi]

mov gapArr[esi], eax

inc esi

loop L1

;Calculate the sum of gaps between array elements

mov sum, 0

mov esi, 0

mov ecx, arrSize

dec ecx

;  move gapArr[esi] to a temporary register and then add that register value to sum

L2:

mov edx, gapArr[esi]  

add sum, edx

inc esi

loop L2

       INVOKE ExitProcess,0

main ENDP

END main

Explanation:

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Which one of the following downloads and uploads files to and from a server? A. Client B. Internet protocol C. Server D. Worksta
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The answer is A. Client request and receive files to and from a server.
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Which of the following is a hand-drawn animation that takes a large amount of time to complete?
elixir [45]

Answer:

Where are the choices?

Thanks for adding the choices at the comment secion

  1. 2D animation
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There are 12 inches in a foot and 3 feet in a yard. Create a class named InchConversion. Its main() method accepts a value in in
Dafna1 [17]

Answer:

import java.util.Scanner;

public class InchConversion

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

   

 System.out.print("Enter inches: ");

 double inches = input.nextDouble();

 

 inchesToFeet(inches);

 inchesToYards(inches);

}

public static void inchesToFeet(double inches){

    double feet = inches / 12;

    System.out.println(inches + " inches = " + feet + " feet");

}

public static void inchesToYards(double inches){

    double yards = inches / 36;

    System.out.println(inches + " inches = " + yards + " yards");

}

}

Explanation:

In the inchesToFeet() method that takes one parameter, inches:

Convert the inches to feet using the conversion rate, divide inches by 12

Print the feet

In the inchesToYards() method that takes one parameter, inches:

Convert the inches to yards using the conversion rate, divide inches by 36

Print the yards

In the main:

Ask the user to enter the inches

Call the inchesToFeet() and inchesToYards() methods passing the inches as parameter for each method

7 0
3 years ago
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