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Nata [24]
3 years ago
12

Find all values of x (if any) where the tangent line to the graph of the given equation is horizontal. HINT [The tangent line is

horizontal when its slope is zero.] (If an answer does not exist, enter DNE. Enter your answers as a comma-separated list.) y = −9x2 − 2x
Mathematics
1 answer:
Nostrana [21]3 years ago
6 0
By "y = −9x2 − 2x" I assume you meant  <span>y = −9x^2 − 2x (the "^" symbol represents exponentiation).

Let's find the first derivative of y with respect to x:  dy/dx = -18x - 2.  This is equivalent to the slope of the tangent line to the (parabolic) curve.  Now let this derivative (slope) = 0 and solve for the critical value:  -18x - 2 = 0, or
-18x = 2.  Solving for x,   x = -2/18,    or    x = -1/9.

When x = -1/9, y = -9(-1/9)^2 - 2(-1/9).  This simplifies to y = -9/9 + 2/9, or 
y = -7/9.

The only point at which the tangent to the curve is horiz. is (-1/9,-7/9).</span>
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Answer:

Correct I think

Step-by-step explanation:

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2 years ago
Write 6(9+2k)= -3 in written form
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Answer:

27k+3=0

Step-by-step explanation:

Write in standard form.

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2 years ago
Someone please help me with this question
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3

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