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3 years ago

WILL GIVE BRAINLEST PLS HELP ASAP LOOK AT IMAGE AND PLS HELP

Mathematics

2 answers:

klasskru [66]3 years ago

8 0

Answer:

Absolute value is 1 1/2

Step-by-step explanation:

Vaselesa [24]3 years ago

7 0

Answer:

2 1/4

Step-by-step explanation:

Absolute value is the distance a point is from 0. Since the point is at 2 1/4, the absolute value is 2 1/4.

-hope it helps

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Plz help with this we are doing coreections

Tanzania [10]

Answer:

the answer is b i think

hope this helps :)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is a point-slope equation of the line with slope - 10 that goes through the point (1.4) Ay- 4 = -10(x - 1) By+43-10(x+1) O

weqwewe [10]

Answer:

y-4=-10(x-1)

Step-by-step explanation:

7 0

3 years ago

Thomas is grandfather's 100 years old. Thomas grandfather is 10 times as old as Thomas. How old is thomas

Diano4ka-milaya [45]

Its one thousand years old because you need to multiply 100 and 10. hope it was useful

4 0

3 years ago

Read 2 more answers

a farmer is planning a rectangular area for her chickens. the area of the rectangle will be 200 square feet. three sides of the

Vladimir79 [104]

Let

x---------> the length side of the rectangular area

y---------> the width side of the rectangular area

we know that

the area of the rectangle is equal to

$A=x*y\\ A= 200\ ft^{2} \\ x*y=200$

$y=\frac{200}{x}$ -----> equation $1$

The perimeter of the rectangle is equal to

$P=2x+2y$

but remember that the fourth side of the rectangle will be formed by a portion of the barn wall

$P=x+2y$ -----> equation $2$

To minimize the cost we must minimize the perimeter

Substitute the equation $1$ in the equation $2$

$P=x+2*[\frac{200}{x} ]$

Using a graph tool

see the attached figure

The minimum of the graph is the point $(20,40)$

that means for $x=20\ ft$

the perimeter is a minimum and equal to $40\ ft$

Find the value of y

$y=\frac{200}{x}$

$y=\frac{200}{20}$

$y=10\ ft$

The cost of fencing is equal to

$5*40= \$200$

therefore

the answer is

the length side of the the fourth wall will be $20\ ft$

7 0

4 years ago

A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of

Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

Step-by-step explanation:

Let X = time spent per week shopping online.

It is provided that the random variable X follows a Poisson distribution.

The probability function of a Poisson distribution is:

$P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...$

The average time spent per week shopping online is, λ = 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

$P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217$

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338$

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

$=\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922$

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0

4 years ago

WILL GIVE BRAINLEST PLS HELP ASAP LOOK AT IMAGE AND PLS HELP​

WILL GIVE BRAINLEST PLS HELP ASAP LOOK AT IMAGE AND PLS HELP