Hey there!
Line passes through (4, -1) & is parallel to 2x -3y=9
Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.
The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.
Start off by subtracting 2x from both sides.
-3y = -2x + 9
Then, divide both sides by -3.
y = (-2x + 9)/-3
Simplify.
y = 2/3x - 3
"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.
We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.
Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).
y-y₁=m(x-x₁)
Let's start by plugging in 2/3 for m (our new slope), 4 for x1 and -1 for y1.
y - (-1) = 2/3(x - 4)
Simplify.
y + 1 = 2/3 + 8/3
Simplify by subtracting 1 from both sides.
y = 2/3x + 8/3 - 1
Simplify.
y = 2/3x + 5/3
~Hope I helped!~
Check the picture below.
make sure your calculator is in Degree mode.
Similarities: They both are polynomials of degree 2, both of their graphs is a parabola, both have either 2 or 0 real solutions, they are both continuous functions over R
<span>(DOS= difference of two squares, PST=perfect square trinomial </span>
<span>Differences: PST has three terms, whereas the difference of squares has 2. PST's factors are both the same, whereas DOS's elements are conjugates of each other. DOS can always be factored into two distinct polynomials with rational coefficients, whereas PST has two same polynomial factors.</span>
