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-BARSIC- [3]
3 years ago
11

A customer desires to mix her own concrete. The clerk knows that the ratio of cement to sand to gravel is 1:3:4. If the customer

needs 1000 pounds of dry mix, how many pounds of each ingredient should she use.
Mathematics
1 answer:
Aleks [24]3 years ago
8 0

Answer:

The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Step-by-step explanation:

Given as :

The ratio of cement to sand to gravel = 1 : 3 : 4

The total quantity of dry mix required = 1000 pounds

Let The quantity of cement required = 1 × x pounds

The quantity of sand required = 3 × x pounds

The quantity of gravel required = 4 × x pounds

So, According to question

The total quantity of dry mix required = The quantity of cement required + The quantity of sand required + The quantity of gravel required

Or, x + 3 x + 4 x = 1000 pounds

Or, 8 x = 1000 pounds

∴  x = \frac{1000}{8}

I.e x = 125

So , The quantity of cement required = 1 × 125 pounds = 125 pounds

The quantity of sand required = 3 × 125 pounds = 375 pounds

The quantity of gravel required = 4 × 125 pounds = 500 pounds

Hence The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Answer

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A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
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Radius =6.518 feet

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Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

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C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

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