If these are terms of a geometric sequence, they have a common ratio. That is, ...
... (k -1)/(2(1 -k)) = (k +8)/(k -1)
... (k -1)² = 2(1 -k)(k +8) . . . . . multiply by the product of the denominators.
... k² -2k +1 = -2k² -14k +16 . . . eliminate parentheses
... 3k² +12k -15 = 0 . . . . . . . . put in standard form (subtract the right side)
... 3(k +5)(k -1) = 0 . . . . . . . . . factor
Possible values of k are ... -5, +1. The solution k=1 is extraneous, as it makes the first two terms 0 and the third term 8. (It doesn't work.)
The value of k is -5.
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The three terms are 12, -6, 3. The common ratio is -1/2.
Answer:
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Options:
A) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
B) Reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
D) Reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Explanation:
The null hypothesis H0: µ=43°F (a true mean temperature maintained by refrigerator is equal to 43°)
The alternative hypothesis Ha: µ<>43 (a true mean temperature maintained by refrigerator is not equal to 43).
A type II error does not reject null hypothesis H0 when it is false. Therefore, the type II error for the test fails to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
It’s about 52. 578•.09=52.02, which rounds to 52.
15. -2
16. A. The pool was originally empty
