Answer:
s = 16.97 units
Step-by-step explanation:
Since this is a right triangle, we can use trigonometry to figure out the lengths of the sides.
Look at the 45 degree angle. We can use the opposite side (12) and the hypotenuse (s) to solve for s.
Opposite and hypotenuse is sine, so we are using sine. The sine of 45 degrees is 0.70710678118. Make an equation like so:
- 0.70710678118 =
, and we are solving for s.
Put a 1 in the denominator of sine(45 degrees) so you can cross-multiply.
Cross multiply.
Divide both sides by sine(45 degrees).
The length of side s is 16.97 units.
Another way to have done this problem is to use the Pythagorean theorem: a^2 + b^2 = c^2
Substitute 12 for a and b and solve for c, the hypotenuse.
Evaluate the exponents.
Add them together.
Square root 288 to solve for c.
c = 16.97, which is the same answer as you got using trigonometry.
Based on the short-term debt that Nelson raises, the firm's quick ratio will be 1.204.
<h3>What is the firm's quick ratio?</h3><h3 />
First, find the maximum amount of short-term funds that Nelson can raise?
Assuming this amount is x, we can find it with the current ratio formula:
Current ratio = Current assets / Current liabilities
2 = (1,260,000 + x) / ( 450,000 + x)
x = $360,000
The quick ratio would therefore be:
= ( New Current assets - New inventory) / New current liabilities
= ( (1,260,000 + 360,000) - (285,000 + 360,000) ) / (450,000 + 360,000)
= 1.204
Find out more on quick ratio at brainly.com/question/13917900.
#SPJ1
Answer:
Step-by-step explanation:
Since it is a regular hexagon, the length of its sides are equal. And same as the distance across its flats.
So that;
NR ≅ OP (property of a regular polygon)
PM ≅ RM (half of the distance across flats of a polygon)
NM ≅ OM (half of the distance across flats of a polygon)
<NMR ≅ <PMO (vertically opposite angles)
<NRM ≅ <OPM (alternate angle property)
<RNM ≅ <POM (alternate angle property)
This therefore proves that: ΔNRM = ΔOPM
There are 23535820 combinations that can be made of 35 calculators taken 8 at a time.
