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4 years ago

Which names are correct for FM−→− ?

Mathematics

2 answers:

fiasKO [112]4 years ago

6 0

Answer with explanation:

⇒A segment , $\Bar {AB}$ is equivalent to $\Bar {BA}$ .

⇒We can assert this by this way, if Distance between Two points A and B is 6 unit, then Distance between B and A will be 6 unit also.

So,

$\bar{FM}=\bar{MF}$

FM−→−⇒MF−→−

Option A

denis-greek [22]4 years ago

6 0

Answer:FP−→− and FD−→−

Step-by-step explanation:

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3 years ago

Put the following equation in standard form and determine the quadratic, linear, and constant coefficients. -3x2 - 8 = 5x - 7

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Answer:

-3x² -5x -1 = 0
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-5 (linear)
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Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

-3x² -8 -(5x -7) = 5x -7 -(5x -7)

-3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

-3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

-3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

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