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vodomira [7]
3 years ago
15

Please help. Also it’s a picture

Mathematics
1 answer:
kiruha [24]3 years ago
4 0
<h3>Answer:  $580.38  (Choice B)</h3>

===================================

Work Shown:

A = P*(1+r/n)^(n*t)

A = 500*(1+0.05/4)^(4*3)

A = 580.3772588615

A = 580.38

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Show the region which satisfies simultaneously the inequalities 2x+3y≤8, x-2y≥-3, x≥0, y≥0
Verizon [17]
The first thing you should do is graph the following lines
 2x + 3y = 8
 x-2y = -3
 x = 0
 y = 0
 After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
 2x + 3y≤8, x-2y≥-3, x≥0, y≥0
 The resulting region is the region "R" shown in the attached graph.

8 0
3 years ago
What angles are they ​
Doss [256]

Answer:

option d. vertical opposite angle

3 0
2 years ago
What is the equation of this line in standard form? 8x−7y=−25 8x−9y=23 8x−9y=−23 9x−8y=23 Number graph ranging from negative fiv
Gnoma [55]

Answer:

The equation of line is:

8x-9y=-23

Step-by-step explanation:

We are given that a graph is  a that passes through two points:

(-4,-1) and (\dfrac{1}{2},3)

We know that the equation of line passing through two points:

(a,b) and (c,d) is given by:

y-b=\dfrac{d-b}{b-a}\times (x-a)

Here we have:

(a,b)=(-4,-1) and (c,d)=(\dfrac{1}{2},3)

Hence, the equation of line is:

y-(-1)=\dfrac{3-(-1)}{\dfrac{1}{2}-(-4)}\times (x-(-4))\\\\y+1=\dfrac{3+1}{\dfrac{1}{2}+4}\times (x+4)\\\\y+1=\dfrac{4}{\dfrac{9}{2}}\times (x+4)\\\\y+1=\dfrac{4\times 2}{9}\times (x+4)\\\\y+1=\dfrac{8}{9}\times (x+4)\\\\9\times (y+1)=8\times (x+4)\\\\9y+9=8x+8\times 4\\\\9y+9=8x+32\\\\8x-9y=9-32\\\\8x-9y=-23

Hence the equation of line is:

8x-9y=-23

5 0
3 years ago
Which expression is equivalent to (3−2^2) 5 ? 5−3^2 5−2^2 2^2−5 ​ 3^2−5
tamaranim1 [39]
Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5
8 0
3 years ago
Help<br> Please I need hekp
AlekseyPX

Answer:

86

Step-by-step explanation:

6 0
3 years ago
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