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4 years ago

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Carbon. We are carbon-based life forms. Carbon cycles between Earth's spheres. When viewing the Earth as a system, the

2 answers:

balu736 [363]4 years ago

6 0

Answer:

C)

Model I distinguishes between natural and anthropogenic flux.

Explanation:

Just took quiz

Ludmilka [50]4 years ago

4 0

Answer:

the answer is c bc i got it wrong on usatestprep bc i picked d and it was c

Explanation:

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Materials essential to life processes move across a cell membrane through a variety of methods. What cell membrane structure all

ElenaW [278]

Answer:

C. carrier proteins

Explanation:

The core of the cell membrane is made up of hydrophobic tails of phospholipid. It does not allow the water-soluble material to move across the membrane. Carrier proteins are the membrane proteins that serve as transporters.

The carrier proteins bind the ion or water-soluble molecules and undergo changes in shape. This transports the molecule across the membrane. Carrier proteins serve in passive facilitated diffusion and active transport. The carrier proteins involved in facilitated diffusion transport the molecules down the concentration gradient without any expenditure of energy.

8 0

3 years ago

Whats glucose without the water molecules?

ANTONII [103]

Answer:

qewfds

Explanation:

8 0

3 years ago

Read 2 more answers

the frequency of a wave in a stretched string depends on the length L, tension T and linear density m with dimension ML-1 . dedu

spin [16.1K]

Answer:

$f = \frac{1 }{L}\sqrt{\frac{T}{m} }$

Explanation:

Let the frequency ,

$f = L^{x}T^{y}m^{z}$

Now the unit of frequency is hertz = s⁻¹ = T⁻¹ where T is time, tension T = kgm/s² = MLT⁻¹ and linear density m = kg/m = ML⁻¹.

So,

$T^{-1} = L^{x}[MLT^{-2} ]^{y}[ML^{-1} ]^{z}\\$

collecting the like bases, we have

$T^{-1} = [L^{x + y -z}][M^{y + z} ][T^{-2y} ] \\L^{0} M^{0} T^{-1} = [L^{x + y -z}][M^{y + z} ][T^{-2y} ]$

Equating powers on both sides, we have

x + y - z = 0 (1)

y + z = 0 (2)

-2y = -1 (3)

From (3), y = 1/2

From (2), z = -y = -1/2

Substituting y and z into (1), we have

x + y - z = 0

x + 1/2 - (-1/2) = 0

x + 1/2 + 1/2 = 0

x + 1 = 0

x = -1

So,

$f = L^{x}T^{y}m^{z}\\f = L^{-1}T^{\frac{1}{2} }m^{\frac{-1}{2} }$

$f = \frac{1 }{L}\sqrt{\frac{T}{m} }$

8 0

3 years ago

A maize plant with genotype Aa Bb produces the following gametes 100 Ab 45 AB 106 aB 50 ab This tells us that the two genes are

bogdanovich [222]

Answer:

True

Explanation:

The linkage relation of two genes can be determined on the basis of calculating recombination frequency.

If the recombination frequency value is greater than 50% then the genes are not linked and if the value is less than 50% then the genes are linked.

In the given question, the crossover gametes formed will be Ab = 100

and aB= 106.

Therefore,

$\dfrac{recombinant\ progenies}{ Total\ progeny}\times 100\\\\\dfrac{100 +106}{100+106+45+50}\times 100\\\\=\dfrac{206}{301}\times 100\\\\= 68.43\%$

Since the recombinant frequency value is larger than 50% therefore the genes do not show linkage.

Thus, True is the correct answer.

7 0

3 years ago

Which of the following is likely to happen in a deforested area?

zheka24 [161]

<span>Increase in soil erosion. hop it helps.</span>

8 0

3 years ago

Read 2 more answers