All categories

4 years ago

the vet charges $45 for an office visit and $10 for each vaccination your dog needs. write an eaquation

Mathematics

1 answer:

ser-zykov [4K]4 years ago

6 0

Answer:

45+10x = y

Step-by-step explanation:

$45 -- stays the same no matter what so that's constant.

$10 -- this varies dependent on the number of vaccinations your dog needs, so you'd use a variable to represent the number of vaccinations (in this case I'm using variable "x").

So, for example if your dog needed 7 vaccinations, it would be: 45+10(7) = y -- answer being $115.

You might be interested in

What is the volume<br> of this triangular prism?<br> 6m<br> 5m<br> 10m

notsponge [240]

Show the picture to answer this

6 0

3 years ago

If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then which statement would be true

Bumek [7]

If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then the figure must be a rhombus because it has exactly 2 pairs of congruent angles.

I hope this helps! :)

3 0

4 years ago

Read 2 more answers

. Two planes are 1620 miles apart and are traveling toward each other. One plane is traveling 120 mph

Nadusha1986 [10]

Answer:

Step-by-step explanation:

let the speed of one plane=x mph

speed of other plane=x+120 mph

x×1.5+(x+120)×1.5=1620

(x+x+120)×1.5=1620

(2x+120)×1.5=1620

3x+180=1620

3x=1620-180

3x=1440

x=480

speed of one plane=480 mph

speed of second plane=480+120=600 mph

4 0

3 years ago

Which expressions are equivalent to \dfrac{4^{-3}}{4^{-1}} 4 −1 4 −3 start fraction, 4, start superscript, minus, 3, end super

Slav-nsk [51]

Answer:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}$

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}$

Step-by-step explanation:

Given

$\dfrac{4^{-3}}{4^{-1}}$

Required

Choose equivalent expressions

Choosing the first answer:

$\dfrac{4^{-3}}{4^{-1}}$

Split expressions

$4^{-3} * \frac{1}{4^{-1}}$

Apply laws of indices: $(a^{-b} = \frac{1}{a^b})$

$\frac{1}{4^3} * \frac{1}{4^{-1}}$

Apply laws of indices: $(a^{-b} = \frac{1}{a^b})$

$\frac{1}{4^3} * \frac{1}{1/4}$

$\frac{1}{4^3} * \frac{4^1}{1}$

$\frac{4^1}{4^3}$

Hence:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}$

Choosing the second:

$\dfrac{4^{-3}}{4^{-1}}$

Apply law of indices: $(\frac{a^m}{a^n} = a^{m-n})$

So,

$\dfrac{4^{-3}}{4^{-1}} = 4^{-3-(-1)}$

$\dfrac{4^{-3}}{4^{-1}} = 4^{-3+1)}$

$\dfrac{4^{-3}}{4^{-1}} = 4^{-2}$

Apply law of indices: $(a^{-b} = \frac{1}{a^b})$

So:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}$

4 0

3 years ago

Please i need help with this please

Over [174]

Answer:

Your answer would be 9.

Step-by-step explanation:

You always do parenthesis first, 9-6 is 3, then you would do division 3÷3 is 1 then you multiply 4×2 and that would be 8, finally you would at the 8 and the 1 and that would give you 9 as your answer. Hope this helps

7 0

3 years ago