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3 years ago

Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.

Mathematics

1 answer:

Sphinxa [80]3 years ago

8 0

Answer:

The required rate of interest = 14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest = Amount - Principal

= 9,000 - 7,000 = 2,000

So, the SI on the given principal for 2 years = 2,000

$\textrm{SIMPLE INTEREST } = \frac{P \times R \times T}{100}\\\implies 2000 = \frac{7,000 \times R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2} = 14.285$

or, R = 14.285%

Hence, the required rate of interest = 14.285%

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Answer:

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point K is between points M and Q. If line segment MK = 7 inches and line segment MQ = 15 inches, whst is the measurement of KQ?

BigorU [14]

The total length of a line segment is the sum of the lengths of its parts.

MQ = MK + KQ . . . . . . express the relationship between the segments

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3 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is