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Radda [10]
3 years ago
8

Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

The required rate of interest   =   14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest  =  Amount - Principal

                                      =  9,000 - 7,000  = 2,000

So, the SI on the given principal for 2 years  = 2,000

\textrm{SIMPLE INTEREST } = \frac{P \times  R \times T}{100}\\\implies 2000 = \frac{7,000 \times  R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2}  = 14.285

or, R =  14.285%

Hence, the required rate of interest   =   14.285%

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