All categories

3 years ago

Need help please! tia

Mathematics

1 answer:

Maslowich3 years ago

6 0

The second one again lol

You might be interested in

Find the solutions to the equation below. Check all that apply. X2 - 9 = 0 O =

Snowcat [4.5K]

9514 1404 393

Answer:

C, D

Step-by-step explanation:

The equation factors as ...

(x -3)(x +3) = 0

The value will be zero when a factor is zero. That is, solutions are ...

x = 3 and x = -3 . . . . . matches choices C and D

3 0

3 years ago

Four friends go out to lunch and decide to split the bill evenly. The bill comes to $48.20. How much does each person owe?

jeka94

Four friends go out to lunch and they agree to split the bill evenly.
so now you have to divide the price by 4 because there's four people.
$48.20. / 4.
so your answer is $12.05 that's so much each person will pay for their share of bill.

8 0

3 years ago

Read 2 more answers

What is the unit value of the 6 in 216?

eduard

The 6 is in the ones place the 1 is in the tens place and the 2 is in the hundreds place.

8 0

3 years ago

Which function does not have a vertical asymptote? A) y=(x) /(1-x²) . B) y=(5x) /(1-2x²) . C) y=(5x-1) /(3+x^2) . D) (5x) /(x+x²

uysha [10]

A function has a vertical asymptote $x=a$ at point a, where the denominator becomes equal to 0.

A. The denominator of the function $f(x)=\dfrac{x}{1-x^2}$ turns into 0 at $x=1$ or $x=-1.$ Then $x=1$ and $x=-1$ are two vertical asymptotes of this function.

B. The denominator of the function $f(x)=\dfrac{5x}{1-2x^2}$ turns into 0 at $x=\sqrt{\frac{1}{2}}$ or $x=-\sqrt{\frac{1}{2}}$ Then $x=\sqrt{\frac{1}{2}}$ and $x=-\sqrt{\frac{1}{2}}$ are two vertical asymptotes of this function.

C. The denominator of the function $f(x)=\dfrac{5x-1}{3+x^2}$ never turns into 0, then this function hasn't any asymptotes.

D. The denominator of the function $f(x)=\dfrac{x}{x+x^2}$ turns into 0 at $x=0.$ Then $x=0$ is vertical asymptote of this function.

Answer: correct choice is C.

5 0

3 years ago

How to find the quotient of r and 12

arlik [135]

You have to give another number to get the answer to this question. I would be happy to answer this if you could give me that other number. This is not an equation.

8 0

3 years ago

Need help please! tia​

Need help please! tia