Question:
Find the gradient of the line passing through (6,8) and (4,10).
Answer:
-1 is the right answer.
Step-by-step explanation:
Slope of the line = The gradient of the line
Gradient of the line is known as change in the value of y-axis by change in the value of x-axis
Gradient = ∆y\∆x

Answer:
C) x/2 +2y = 4
Step-by-step explanation:
Of the equations offered, only equation C has the given point as a possible solution.
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Since the graph is not given, we don't know if the given point is on the graphed equation.
Umm, I need the numbers that are given but I can give you examples. It can be 5 1/6 or like 5 4/9
The whole number needs to be bigger
Answer:
1. 10x^2 -4
2. 2a^5 + 5b
Step-by-step explanation:
1. Simplify 4(x^2 -1) to 4x^2 -4
then add that to 6x^2
2. 4a^5 - 2a^5 = 2a^5 and
4b+b = 5b
Answer:
a) 0.125
b) 7
c) 0.875 hr
d) 1 hr
e) 0.875
Step-by-step explanation:l
Given:
Arrival rate, λ = 7
Service rate, μ = 8
a) probability that no requests for assistance are in the system (system is idle).
Let's first find p.
a) ρ = λ/μ

Probability that the system is idle =
1 - p
= 1 - 0.875
=0.125
probability that no requests for assistance are in the system is 0.125
b) average number of requests that will be waiting for service will be given as:
λ/(μ - λ)
= 7
(c) Average time in minutes before service
= λ/[μ(μ - λ)]
= 0.875 hour
(d) average time at the reference desk in minutes.
Average time in the system js given as: 1/(μ - λ)

= 1 hour
(e) Probability that a new arrival has to wait for service will be:
λ/μ =
= 0.875