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svet-max [94.6K]
3 years ago
10

What is 12-(16)= lollolll

Mathematics
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

-4

Step-by-step explanation:

pls give brainliest

bekas [8.4K]3 years ago
5 0

Answer:

-4

Step-by-step explanation:

12-16 is -4

have a GREat day

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An equestrian club orders magazine subscriptions for new members.
lukranit [14]

Answer: The cost for each subscription is $19.5

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Simplify 8 over negative 4 divided by negative 3 over 9. 6 −6 12 −12
skelet666 [1.2K]

Answer:

6

Step-by-step explanation:

Given

\frac{8}{-4} /  \frac{-3}{9}

Required

Solve

\frac{8}{-4} /  \frac{-3}{9}

We start by converting the division sign to multiplication

\frac{8}{-4} /  \frac{-3}{9} =\frac{8}{-4} *  \frac{-9}{3}

Then, we divide -9 by 3

\frac{8}{-4} /  \frac{-3}{9}=\frac{8}{-4} *  -3

Then, we divide 8 by -4

\frac{8}{-4} /  \frac{-3}{9}=-2 *  -3

Multiply -2 and -3 to give final result

\frac{8}{-4} /  \frac{-3}{9} = 6

Hence, \frac{8}{-4} /  \frac{-3}{9} is equivalent to 6

4 0
3 years ago
I need help on this ASAP!!
vazorg [7]
The answer is 16 units
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So in this case, you count how many units each line of the triangle it covers. 4+6+6= 16
7 0
3 years ago
He vertices of square pqrs are p -4,0 q 4,3 r 7,-5 and s -1,-18.Show that the diagonals of square pqrs are congruent perpendicul
Anit [1.1K]

Answer:

Step-by-step explanation:

The vertices of the square given are P(-4, 0), Q(4, 3), R(7, -5) and, S(-1, -18)

For this diagonal to be right angle the slope of the diagonal must be m1=-1/m2

So let find the slope of diagonal 1

The two points are P and R

P(-4, 0), R(7, -5)

Slope is given as

m1=∆y/∆x

m1=(y2-y1)/(x2-x1)

m1=-5-0/7--4

m1=-5/7+4

m1=-5/11

Slope of the second diagonal

Which is Q and S

Q(4, 3), S(-1, -18)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-18-3)/(-1-4)

m2=-21/-5

m2=21/5

So, slope of diagonal 1 is not equal to slope two

This shows that the diagonal of the square are not diagonal.

But the diagonal of a square should be perpendicular, this shows that this is not a square, let prove that with distance between two points

Given two points

(x1,y1) and (x2,y2)

Distance between the two points is

D=√(y2-y1)²+(x2-x1)²

For line PQ

P(-4, 0), Q(4, 3)

PQ=√(3-0)²+(4--4)²

PQ=√(3)²+(4+4)²

PQ=√9+8²

PQ=√9+64

PQ=√73

Also let fine RS

R(7, -5) and, S(-1, -18)

RS=√(-18--5)+(-1-7)

RS=√(-18+5)²+(-1-7)²

RS=√(-13)²+(-8)²

RS=√169+64

RS=√233

Since RS is not equal to PQ then this is not a square, a square is suppose to have equal sides

But I suspect one of the vertices is wrong, vertices S it should have been (-1,-8) and not (-1,-18)

So using S(-1,-8)

Let apply this to the slope

Q(4, 3), S(-1, -8)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-8-3)/(-1-4)

m2=-11/-5

m2=11/5

Now,

Let find the negative reciprocal of m2

Reciprocal of m2 is 5/11

Then negative of it is -5/11

Which is equal to m1

Then, the square diagonal is perpendicular

6 0
3 years ago
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