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3 years ago

9

Determine whether the polygons with the given vertices are congruent. support your answer by describing a transformation:

1 answer:

dsp733 years ago

7 0

<span>In this question, you would like to know weather the polygons with their given vertices are congruent and would like for the answer to be supported by a description of a transformation. A (2,-1), B (3,0), C (2,3) and P (1,2), Q (0,3), E (-3, 2). The triangles can be labeled as congruent because you can map ABC to PRQ by a simple rotation : (x,y) --> (-y,x).</span>

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Find the inverse of the function.<br> y = x2 + 4x + 4

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Answer:

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pentagon [3]

The answer would be -9/40

Here’s how you solve it!

Use PEMDAS through out the whole process

Anything that I should multiplied by 1 stays the same so you can multiply the 1 first so your equation looks like this:

3✖️1/8✖️(2/3➕2✖️2/3✖️(1/4➖6/5))

Now subtract the fractions that are in the parentheses, subtract 1/4➖6/5 so your equation looks like this:

3✖️1/8✖️(2/3➕2✖️2/3✖️(➖19/20))

Since a positive multiplied by a negative equals a negative change the sign so your equation should look like this:

3✖️1/8✖️(2/3➖2✖️2/3✖️19/20)

Then use the greatest common divisor and reduce it by 2

3✖️1/8✖️(2/3➖2/3✖️19/10)

Then reduce again

3✖️1/8✖️(2/3➖1/3✖️19/5)

Then multiply the two factors so it now looks like this:

3✖️1/8✖️(2/3➖19/15)

Now subtract what’s in the parentheses so you get this:

3✖️1/8✖️(➖3/5)

Since a positive multiplied by a negative equals a negative it will now look like this:

➖3✖️1/8✖️3/5

Now all you have to do left is calculate the product to get your answer:

-9/40

Hope this helps! :3

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4 years ago