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Lubov Fominskaja [6]
3 years ago
12

Please find <TQU in the question above ​

Mathematics
1 answer:
Mumz [18]3 years ago
5 0

Answer:

<TQU = 72°

Step-by-step explanation:

<WQT = 60°

=> <WQT = <UYX <u><em>(corresponding angles)</em></u>

=> <UYX = <YUV <u><em>(alternate angles)</em></u>

=> <YUV = <UQR <u><em>(corresponding angles)</em></u>

So, <UQR = 60°

Now,

<PQT+<TQU+<UQR = 180° <u><em>(angles on a straight line add up to 180°)</em></u>

48° + <TQU + 60° = 180°

<TQU + 108 = 180

Subtracting 108 from both sides

<TQU = 180-108

<TQU = 72°

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