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Colt1911 [192]
2 years ago
11

Write the equation log216 36=36 in logarithmic form

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
3 0
This is impossible and it is not even an equation since \log_{216} 36 = 2/3
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In parallelogram ABCD, AD = 4x - 10 and BC = 3x + 2. Find AD.
Helga [31]

Answer:12


Step-by-step explanation:

4x - 10= 3x+2 add 10= 4x = 3x+12 subtract 3x=1x 1x=12 divide 12 by 1=12 should be 12 sorry if I got it wrong...

8 0
3 years ago
If bolt thread length is normally distributed, what is the probability that the thread length of a randomly selected bolt is Wit
KatRina [158]

Answer:

a) 0.5762

b) 0.0214

c) 0.2718

Step-by-step explanation:

It is given that lengths of the bolt thread are normally distributed. So in order to find the required probability we can use the concept of z distribution and z scores.

Part a) Probability that length is within 0.8 SDs of the mean

We have to calculate the probability that the length of a bolt thread is within 0.8 standard deviations of the mean. Recall that a z- score tells us that how many standard deviations away a value is from the mean. So, indirectly we are given the z-scores here.

Within 0.8 SDs of the mean, means from a score of -0.8  to +0.8. i.e. we have to calculate:

P(-0.8 < z < 0.8)

We can find these values from the z table.

P(-0.8 < z < 0.8) = P(z < 0.8) - P(z < -0.8)

= 0.7881 - 0.2119

= 0.5762

Thus, the probability that the thread length of a randomly selected bolt is within 0.8 SDs of its mean value is 0.5762

Part b) Probability that length is farther than 2.3 SDs from the mean

As mentioned in previous part, 2.3 SDs means a z-score of 2.3.

2.3 Standard Deviations farther from the mean, means the probability that z scores is lesser than - 2.3 or greater than 2.3

i.e. we have to calculate:

P(z < -2.3 or z > 2.3)

According to the symmetry rules of z-distribution:

P(z < -2.3 or z > 2.3) = 1 - P(-2.3 < z < 2.3)

We can calculate P(-2.3 < z < 2.3) from the z-table, which comes out to be 0.9786. So,

P(z < -2.3 or z > 2.3) = 1 - 0.9786

= 0.0214

Thus, the probability that a bolt length is 2.3 SDs farther from the mean is 0.0214

Part c) Probability that length is between 1 and 2 SDs from the mean value

Between 1 and 2 SDs from the mean value can occur both above the mean and below the mean.

For above the mean: between 1 and 2 SDs means between the z scores 1 and 2

For below the mean: between 1 and 2 SDs means between the z scores -2 and -1

i.e. we have to find:

P( 1 < z < 2) + P(-2 < z < -1)

According to the symmetry rules of z distribution:

P( 1 < z < 2) + P(-2 < z < -1) = 2P(1 < z < 2)

We can calculate P(1 < z < 2) from the z tables, which comes out to be: 0.1359

So,

P( 1 < z < 2) + P(-2 < z < -1) = 2 x 0.1359

= 0.2718

Thus, the probability that the bolt length is between 1 and 2 SDs from its mean value is 0.2718

4 0
3 years ago
Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water
nekit [7.7K]
<span>The table must show: Time (minutes) number of gallons remaining X y 0 Yo 1 Yo – 1.5 2 Yo – 2*1.5 3 Yo – 3*1.5 4 Yo – 4*1.5 And the equation will be ; Y = Yo – 1.5 x, where Yo is the initial amount of water in the bathtub.</span>
3 0
3 years ago
Please help me out! Will mark brainliest!
Gre4nikov [31]

Answer:

Add -3+8

Step-by-step explanation:

You would do this first because it is in the brackets. Usually you would do (*) first but those are just there because the 4 is negative and if they were not there it would get confusing and look like this::[-3+8]--4. So the next step would be the [*].

HOPE THIS HELPS!!!

3 0
3 years ago
Read 2 more answers
It takes 42 cherries to make a cherry pie. If a chef bought 444 cherries, the last pie would need how many more cherries?
jeka94
It takes 42 cherries to make a cherry pie.
If a chef bought 444 cherries and you would like to know how many more cherries would the last pie need, you can calculate this using the following steps:

444 / 42 = 74 / 7 = 10 4/7 pies

4/7 * 42 = 24 cherries

42 - 24 = 18 more cherries

Result: The last pie would need 18 more cherries.
3 0
3 years ago
Read 2 more answers
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