Answer:
Your answer is <em>I think </em>A) A loop
Explanation:
In computer programming, a loop is a sequence of instruction s that is continually repeated until a certain condition is reached.
Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
<span>The answer is Ten. Substituting numbers for letters, available selections are 111, 112, 113, 122, 123, 133, 222, 223, 233, 333. Note that, for example, 112, 121, and 211 are considered as the same selection.
</span>AAA, BBB, CCC, <span>AAB, AAC, </span><span>BBC, </span><span>ABB, ACC, </span><span>CCB & ABC.</span>
<span>The following statements are true:
1. Leased lines require little installation and maintenance expertise.
( A high service quality is offered by point-to point system)
2. Leased lines provide highly flexible bandwidth scaling.
(This Allows a Constant availability)</span>