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iren [92.7K]
4 years ago
9

(5xy^2-x^2y)+3x^2y Equals what?

Mathematics
1 answer:
Savatey [412]4 years ago
6 0

(5xy^2-x^2y)+3x^2y=5xy^2+(-x^2y+3x^2y)\\\\=5xy^2+2x^2y

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Is the orthocenter of a triangle on the inside ?
likoan [24]

Answer:

It turns out that all three altitudes always intersect at the same point - the so-called orthocenter of the triangle. The orthocenter is not always inside the triangle. If the triangle is obtuse, it will be outside. To make this happen the altitude lines have to be extended so they cross.

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Help please im failing‍♀️
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Answer:

$17.0625

Step-by-step explanation:

9.75 a ticket

As it is 15% every year, in 5 years it would cost 75% more

75% of 9.75 is 7.3125

9.75 + 7.3125 = 17.0625

4 0
3 years ago
Solve the following equation for x. x = -2 x = 2 x = -17 x = -7 (x - 5)/2 = -6
nordsb [41]

Step-by-step explanation:

x= -2,

(x - 5) / 2= -6

( (-2) - 5) / 2= -6

(-7) / 2 = -6

-3.5 = - 6

right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.

x=2,

(x - 5) / 2= -6

(2 - 5) / 2= -6

(-3) / 2= -6

-1.5 = - 6

right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.

x= -17

(x - 5) / 2= -6

( ( -17) - 5) / 2= -6

(- 22) / 2= -6

-11 = -6

right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.

x= -7,

(x - 5) / 2= -6

( ( -7) -5) / 2= -6

(-12) / 2= -6

-6= -6

right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.

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3 years ago
Find all solutions of e^(e^z)=1
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Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
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Solve |2x - 1| + 3 = 6.
umka21 [38]

Answer:

x =2                         x = -1

Step-by-step explanation:

|2x - 1| + 3 = 6.

Subtract 3 from each side

|2x - 1| + 3-3 = 6-3

|2x - 1|= 3

An absolute value has two solutions, one positive and one negative

2x-1 =3                   2x -1 = -3

Add 1 to all sides

2x-1+1 =3+1             2x-1+1 = -3+1

2x = 4                      2x =-2

Divide by 2

2x/2 = 4/2                 2x/2 = -2/2

x =2                         x = -1

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