Answer:
Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.
Step-by-step explanation:
Would need the net to answer. but to find the answer you need to find the slant height of the square pyramid, the slant height is the hypotenuse of the right triangle formed by the height and half the base length. Use the pythagorean Theorem
Answer:
the area of the mat = total area added minus the original area of the water color painting.
length of the mat is:
L = 21 in + 3 in + 3 in because 3 in is added to each side
L = 27 inwidth of the mat is:w = 11 in + 3 in + 3 inw = 17in
Area mat = (27 in x 17 in) - ( 21 in x 27 in)
area mat = 108 sq in is the area of the mat
The given polynomial has a degree of 4, the leading coefficient is 3, and the constant is 4.4.
<h3>What is a polynomial?</h3>
A polynomial is an algebraic expression with terms that are the combination of variables, coefficients, and constants.
- The highest power of the variable is said to be the degree of the polynomial.
- The coefficient of the highest power variable is said to be the leading coefficient.
<h3>Calculation:</h3>
The given polynomial is
g(x) = 13.2x³ + 3x⁴ - x - 4.4
The highest power of the variable x is 4. So, the degree of the variable is 4.
Then, the leading coefficient is 3.
The constant on the given polynomial is 4.4.
Learn more about polynomials here:
brainly.com/question/1600696
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Disclaimer: The given question on the portal was incomplete. Here is the complete question.
Question: For the given polynomial, identify the degree, leading coefficient, and the constant value.
g(x) = 13.2x³ + 3x⁴ - x - 4.4
<span>The correct answer is 6.
The clearest way to determine this is by creating a table of possible hand shaking. If we label the people A-D, the following are the ways they can be combined:
AB
AC
AD
BC
BD
CD
There are no other combinations. </span>
