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vodka [1.7K]
3 years ago
10

Which point, (5/2, 3) or (3/2, 20), is on the graph of 2x - 2/3y =3? show steps pls!

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0
You should try both points
put  x=5/2 and y=3
5-2=3
the first one is on the graph
put  x=3/2 and y=20
3-40/3≠3
the second one is not on the graph


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Mrs.scott has 30 pairs of shoes.Out of the 30 pairs 24 of them are black.what percent of shoes are black
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How do you do 3(4y-7)=15y+6​
cestrela7 [59]

Answer:

y = 27/7

Step-by-step explanation:

Perform the indicated multiplication:

3(4y-7)=15y+6 becomes:

12y - 21 = 5y + 6

Combining like terms, we get:

7y = 27, so that y = 27/7

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If g(x) is a translation of f (x) =x^2 right by 5 units and down 3 units which is g(x) ? Please help me ASAP
Contact [7]

Answer:

C

Step-by-step explanation:

Given f(x) then f(x + h) represents a horizontal translation of f(x)

• If h > 0 then a shift to the left of h units

• If h < 0 then a shift to the right of h units

Here the shift is 5 units right, thus g(x) = (x - 5)²

Given f(x) then f(x) + c represents a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Here the shift is 3 units down, thus g(x) = f(x) - 3

Hence

g(x) = (x - 5)² - 3 → C

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2 years ago
which expressions are equivalent to the first one? I don't understand how to determine that so please explain. Thanks!​
coldgirl [10]

9514 1404 393

Answer:

  (a) -(x+7)/y

  (b) (x+7)/-y

Step-by-step explanation:

There are several ways you can show expressions are equivalent. Perhaps the easiest and best is to put them in the same form. For an expression such as this, I prefer the form of answer (a), where the minus sign is factored out and the numerator and denominator have positive coefficients.

The given expression with -1 factored out is ...

  \dfrac{-x-7}{y}=\dfrac{1(x+7)}{y}=\boxed{-\dfrac{x+7}{y}} \quad\text{matches A}

Likewise, the expression of (b) with the minus sign factored out is ...

  \dfrac{x+7}{-y}=\boxed{-\dfrac{x+7}{y}}

On the other hand, simplifying expression (c) gives something different.

  \dfrac{-x-7}{-y}=\dfrac{-(x+7)}{-(y)}=\dfrac{x+7}{y} \qquad\text{opposite the given expression}

__

Another way you can write the expression is term-by-term with the terms in alpha-numeric sequence (so they're more easily compared).

  Given: (-x-7)/y = (-x/y) +(-7/y)

  (a) -(x+7)/y = (-x/y) +(-7/y)

  (b) (x+7)/(-y) = (-x/y) +(-7/y)

  (c) (-x-7)/(-y) = (x/y) +(7/y) . . . . not the same.

__

Of course, you need to know the use of the distributive property and the rules of signs.

  a(b+c) = ab +ac

  -a/b = a/(-b) = -(a/b)

  -a/(-b) = a/b

__

<u>Summary</u>: The given expression matches (a) and (b).

_____

<em>Additional comments</em>

Sometimes, when I'm really stuck trying to see if two expressions are equal, I subtract one from the other. If the difference is zero, then I know they are the same. Looking at (b), we could compute ...

  \left(\dfrac{-x-7}{y}\right)-\left(\dfrac{x+7}{-y}\right)=\dfrac{-y(-x-7)-y(x+7)}{-y^2}\\\\=\dfrac{xy+7y-xy-7y}{-y^2}=\dfrac{0}{-y^2}=0

Yet another way to check is to substitute numbers for the variables. It is a good idea to use (at least) one more set of numbers than there are variables, just to make sure you didn't accidentally find a solution where the expressions happen to be equal. We can use (x, y) = (1, 2), (2, 3), and (3, 5) for example.

The given expression evaluates to (-1-7)/2 = -4, (-2-7)/3 = -3, and (-3-7)/5 = -2.

(a) evaluates to -(1+7)/2 = -4, -(2+7)/3 = -3, -(3+7)/5 = -2, same as given

(b) evaluates to (1+7)/-2 = -4, (2+7)/-3 = -3, (3+7)/-5 = -2, same as given

(c) evaluates to (-1-7)/-2 = 4, different from given

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