One km is about 0.621371 so then you do 400/0.621371 which is 643.738 then you have your answer.400m:643.738km
Answer:
The length of PR is 15.8 cm
Step-by-step explanation:
We will solve the question using the cosine rule
In ΔPQR
∵ (PR)² = (PQ)² + (RQ)² - 2(PQ)(RQ)(cos∠Q)
∵ PQ = 17.8 cm
∵ RQ = 26.3 cm
∵ m∠Q = 36°
→ Substitute them in the rule above
∵ (PR)² = (17.8)² + (26.3)² - 2(17.8)(26.3)(cos36)
∴ (PR)² = 316.84 + 691.69 - 936.28(cos36)
∴ (PR)² = 251.0635685
→ Take √ for both sides
∴ PR = 15.8449856
→ Correct it to 3 significant figures
∴ PR = 15.8 cm
∴ The length of PR is 15.8 cm
Answer:
4.692 to 7.308
Step-by-step explanation:
Given :
n1 = 25 ; n2 = 20 ;
Mean x1 = $12 ; mean x2 = $6
Standard deviation, s1 = 3 ; s2 = 1
Confidence interval :
(x1 - x2) ± t*√(s1²/n1) + (s2²/n2)
x1 - x2 = (12 - 6) = 6
√(s1²/n1) + (s2²/n2) = √(3²/25) + (1²/20) = 0.640
Degree of freedom :
((s1²/n1) + (s2²/n2))² / (s1²/n1)²/n1-1 + (s2²/n2)²/n2-1
Numerator = 0.1681
Denominator = 0.0054 + 0.0001315 = 0.0055315
Degree of freedom = 0.1681 / 0.0055315 = 30.38 = 30
Tcritical at 0.05, df = 30 = 2.042272
Hence ;
6 ± 2.042272(0.640)
6 ± 1.30705408
Lower boundary = 6 - 1.30705408 = 4.69294592
Upper boundary = 6 + 1.30705408 = 7.30705408
(4.693 ; 7.307)
14.
1st, you would take 18 and subtract it from it self and 32. Then you’ll have your answer.