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expeople1 [14]
3 years ago
7

All roses in a certain arrangement are red or yellow. If the ratio of red roses to the number of yellow roses is 1/2, each of th

e following could be the number of roses in the arrangement EXCEPT:
A. 6
B. 10
C. 12
D. 18
E. 24
Mathematics
1 answer:
kondaur [170]3 years ago
4 0
A) 6
B)10
C)12
D)18
E)24

Awnser is C
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3 years ago
When 36 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
Sloan [31]

Answer:

n = -4

Step-by-step explanation:

If we subtract 36 from the square of that number, X^2 - 36 ...

The result is equal to 5 times the number, 5X

Therefore,

X^2 - 36 = 5X

You've probably seen this solved by putting the equation in the form:

aX^2 - bX - c = 0

Doing that here, we subtract 5X from both sides to make the right side of the equation equal to zero.

X^2 - 5X - 36 = 0

Now we need to factor this.

(X _ _ )(X _ _ ) = 0 (where _ denotes an operator or term that we need.)

Looking at the operators, we see that the operands are different, so

(X - _ )(X + _ ) = 0 (we have operator, need term.)

Now we need to find two factors of 36 whose difference is 5. So let's try a few:

36 = 6 X 6 Nope

36 = 12 X 3 Nope

36 = 9 X 4 Yup!

Since the middle term is negative, we know the placement of the 9 and 4.

(X-9)(X+4)= 0

Therefore, X-9=0 or X+4=0

X-9=0 => X=9

X+4=0 => X=-4

Going back to the original problem, it says "Find the negative solution."

Therefore, X=-4.

Let's check:

(-4)^2-36 = 5*(-4)

16-36 = -20

-20=-20 Check!

3 0
4 years ago
Plz help will mark you as brainliest​
zvonat [6]
The answer is B 81 degrees
6 0
3 years ago
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DE + EF = DF.<br> DF = EF.<br> D = F.<br> DF + EF = DE.
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3 years ago
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This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
3 years ago
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