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3 years ago

PleaseI really need help on this please

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

mamaluj [8]3 years ago

3 0

Answer:

Step-by-step explanation:

the anwser to number 7 is d or (x2-4) (x2+4)

by the way try using the app called Photo Math i use it for my test it works greatyou should try it some day.

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PLEASE HELP:))))))) 15points

Zielflug [23.3K]

Answer:7 cm

Step-by-step explanation: you know everything except the radius. Use this equation to help you: 44=2*pi*radius

Divide 44 by 2pi. Then u have your radius which is 7

7 0

3 years ago

HELP ME I DON'T UNDERSTAND THIS :(

andriy [413]

Answer:

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

$\frac{AD}{WZ}$ = $\frac{CD}{YZ}$ , substitute values

$\frac{10}{46}$ = $\frac{5}{YZ}$ ( cross- multiply )

10YZ = 230 ( divide both sides by 10 )

YZ = 23 → c

3 0

3 years ago

Pythagorean theorem to find the length of the hypotenuse in the triangle 16 30

pishuonlain [190]

Answer:

the answer is 34.

Step-by-step explanation:

3 0

2 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv

Cloud [144]

Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.

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8 0

3 years ago