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rjkz [21]
3 years ago
9

darcy likes to eat peanut butter and raisins on apple slices. on each apple slice she puts 1/16 cup of peanut butter and 8 raisi

ne.Darcy has 2/5 cup of peanut butter and 80 raisins . She eats a whole number of apple slice until the peanut butter is all gone . what fraction of the 80 raisins did she eat ?
Mathematics
1 answer:
netineya [11]3 years ago
4 0
The answer is 7/10.

For one apple slice, Darcy needs 1/16 cup of peanut butter and 8 raisins. She has 2/5 cup of peanut butter. To compare how many butter she has and she needs we will divide 2/5 with 1/1

This means that Darcy needs 5/80 cup of peanut butter <span>and 8 raisins.
If she has 32/80 cup of peanut butter, she will have it only fo 6 or 7 apple slices (32/80 </span>÷ 5/80 = 6.4) depending how it is rounded. If she prepares 6 apple slices, she will still have a little of peanut butter left (0.4 = 2/5 of cup). So, she will prepare 7 apple slices so the butter will be all gone.

For 7 apple slices, she needs 56 raisins (7 × 8 raisins).
That is 56 raisins out of 80 raisins, so <span>fraction of the 80 raisins did she eat is:
</span><span>\frac{56}{80} = \frac{7}{10}</span>
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5 0
3 years ago
Read 2 more answers
A university administrator was interested in determining if there was a difference in the distance students travel to get from c
eduard

Answer:

1) Fail to reject the Null hypothesis

2) We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.

Step-by-step explanation:

A university administrator wants to test if there is a difference between the distance men and women travel to class from their current residence. So, the hypothesis would be:

H_{o}: \mu_{F}-\mu_{M}=0\\\\ H_{a}: \mu_{F}-\mu_{M}\neq 0

The results of his tests are:

t-value = -1.05

p-value = 0.305

Degrees of freedom = df = 21

Based on this data we need to draw a conclusion about test. The significance level is not given, but the normally used levels of significance are 0.001, 0.005, 0.01 and 0.05

The rule of the thumb is:

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No matter which significance level is used from the above mentioned significance levels, p-value will always be larger than it. Therefore, we fail to reject the null hypothesis.

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7 0
3 years ago
Calculate the (modeled) probability P(E) using the given information, assuming that all outcomes are equally likely.
Luba_88 [7]

The probability P(E) is 13/15.

According to the statement

we have given that the S = {1, 3, 5, 7, 9}, E = {1, 5, 7}

And we have to find the probability P(E).

So, For this purpose

Recall the formula for the probability of an event E in case when all outcomes are equally likely:

P(E)= n(E) /n(S)

in which S is the sample space.

But we have the S = {1, 3, 5, 7, 9},

so, n(S) = Sum of all outcomes / number of outcomes

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For n(E) = Sum of all outcomes / number of outcomes

n(E) = 1+5+7 /3

n(E) = 13 /3

n(E) = 13 /3

Substitute these values in the above written formula then

P(E)= n(E) /n(S)

P(E)=  (13/3)/ 5

P(E)= 13 /15

So, The probability P(E) is 13/15.

Learn more about the PROBABILITY here brainly.com/question/25870256

#SPJ4

5 0
1 year ago
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