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mihalych1998 [28]
3 years ago
12

Joshua's family took a road trip to Mount Rushmore. Joshua fell asleep 35% of the way through the trip. If the total length of t

he trip was 400 miles, how many miles had they travelled when Joshua fell asleep?
Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
8 0

Answer:

600

Step-by-step explanation:

stiks02 [169]3 years ago
4 0
You need to calculate 35% of 400.

The way I do this on paper is I split it up into chunks and then add the chunks together.

First I would calculate 10%. To do this, divide 400 by 10, because to get from 100% to 10% you must divide by 10.

So 10% = 40

You need 30%, so you just multiply by 3, because to get from 10% to 30%, you multiply by 3.

So 30% = 120

5% is half of 10% so half of 40 is 20.

So 5% = 20

30% + 5% = 35%

120 + 20 = 140

So they had traveled 140 miles when Joshua fell asleep. Hope this helps :)
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Answer:

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Step-by-step explanation:

Given:

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- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

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                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

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                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

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                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

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3 years ago
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