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Genrish500 [490]
3 years ago
14

Whats the vertex form of y=x^2-20x+15

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
This looks like a parabola so:
y=x^2 - 20x + 15  -->  x^2 - 20x +15=y
(x^2 -20x)=y - 15  -->  (x - 10)^2=y - 15 +100  ( used complete the square)
(x - 10)^2=y + 85

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The inverse of the function f(x)  = 4(x-3)² + 2 is f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

The given function is:

f(x)   =  4(x  - 3)²  +  2

To find the inverse of the function:

Make x as the subject of the formula

4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3

Replace x by f^{-1}(x) and replace f(x) by x

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Therefore, the inverse of the function is:

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Learn more here: brainly.com/question/17285960

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