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2 years ago

Factor the following trinomial, if possible 4x^2 + 4x - 3

1 answer:

6 0

<u> $4x^2+\underbrace{4x}_{6x-2x}-3=2x\cdot2x+\underbrace{2x\cdot3}_{6x}-1\cdot2x-1\cdot3\\\\=2x(2x+3)-1(2x+3)=\boxed{\boxed{(2x+3)(2x-1)}}$ </u>

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Which expressions are equivalent to 2 ln a 2 ln b - ln a? Check all that apply. Ln ab2 - ln a ln a 2 ln b ln a2 ln b2 - ln a 2 l

marysya [2.9K]

Equivalent expressions are expressions with same simplified form. Equivalent expressions for the given expression are;

Expression 2: $\ln(a) + 2\ln(b) = \ln(a) + \ln(b^2) = \ln(ab^2)$
Expression 3: $\ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)$
Expression 5: $\ln(ab^2)$

<h3>What are equivalent expressions?</h3>

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

$a^b = c$

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

$b = log_a(c)$

Some properties of logarithm are:

$log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1\\\\ log_a(b) + log_b(c) = log_a(c)$

Log with base e = 2.71828.... is written as $\ln(x)$ simply.

The expression given is $2\ln(a) + 2\ln(b) - \ln(a)$

We get its simplified form as

$2\ln(a) + 2\ln(b) - \ln(a) = \ln(a) + \ln(b^2) = \ln(ab^2)$

Simplifying given expressions:

Expression 1: $\ln(ab^2) - \ln(a) = \ln(ab^2/a) = \ln(b^2)$

This isn't same as simplified form of original

. Thus , this expression is not equivalent to the given expression.

Expression 2: $\ln(a) + 2\ln(b) = \ln(a) + \ln(b^2) = \ln(ab^2)$

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

Expression 3: $\ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)$

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

Expression 4: $2\ln(ab) = \ln((ab)^2) = \ln(a^2b^2)$

This isn't same as simplified form of original expression. Thus , this expression is not equivalent to the given expression.

Expression 5: $\ln(ab^2)$

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

Thus, equivalent expressions for the given expression are;

Expression 2: $\ln(a) + 2\ln(b) = \ln(a) + \ln(b^2) = \ln(ab^2)$
Expression 3: $\ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)$
Expression 5: $\ln(ab^2)$

Learn more about equivalent expressions here:

brainly.com/question/10628562

4 0

1 year ago

Can someone answer these for me please. I need the answers within the next few hours.

FinnZ [79.3K]

Answer: this was all i knew how to do, hope it helps:)

4 0

1 year ago

Help quickly! 10 points!

german

The answer is vertex

6 0

3 years ago

Find the area of the shaded region. Round the the nearest tenth.

Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = $\frac{\theta}{360^{\circ} }\pi r^2$

Area of sector = $\frac{123}{360} \times 3.14 \times (18.6)^2$

Area of sector = $371.157 m^2$

Area of triangle = $\frac{1}{2} \times a \times b \times Sin x$

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = $\frac{1}{2} \times 18.6 \times 18.6 \times Sin 123$

Area of triangle = $145.073 m^2$

So, Area of shaded region = Area of sector - Area of triangle

= $371.157 m^2-145.073 m^2$

= $226.084 m^2$

Hence the area of the shaded region is 226.084 sq.m.

5 0

3 years ago

Raul has been offered three different jobs and must choose which one to accept. One of the factors he is considering is the pay

chubhunter [2.5K]

Answer:

As the pay rate for Job C is the highest, so he must accept the offer from Job C.

Step-by-step explanation:

Given that Raul would work 50 weeks of the year,

40 hours each week,

5 days each week,

and he would receive a 1-hour lunch break each day.

Pay rate for Job A = $35,000 / year

For Job B:

Pay rate = $15 / hour

He will work 40 hours each week.

As he works 5 days a week, so in 1 day he will work 40/5 = 8 hours.

He would receive a 1-hour break each day, for which he will not be paid, so he will receive a payment for 8-1=7 hours.

So, payment for 1 day = $15 x 7 = $105

As he works 5 days a week, so payment for 1 week = $105 x 5 = $525

As he works 50 weeks a year, so payment for 1 year = $525 x 50 = $26250.

So, the pay rate by Job B = $26250 /year

For Job C:

Pay rate = $750 / week

As he works 50 weeks a year, so payment for 1 year = $750 x 50 = $37500.

So, the pay rate by Job C = $37500 /year

As the pay rate for Job C is the highest, so he must accept the offer from Job C.

8 0

2 years ago