The line segments between (4,-6) and (-6,-16) is 1.
slope = y2 -y1 /x2-x1 = -16+6/-6-4=-10/-10=1
Answer:
- x = 7
- x = 11
- 5
Step-by-step explanation:




◇◇•◇◇





♤♤•♤♤



4x - y + 3 =0 is the equation of the line
Step-by-step explanation:
Given:
The slope of the line = 5
The points through with the line passes = (0,3)
To Find:
The equation of the line =?
Solution:
The equation y = mx + b
where m is the slope and (0,b) is the y-intercept.
The slope is given which is m = 4 and a point (0,3)
Then you can use slope-point equation

where
is the given point
y - (3) = 4(x - 0)
y - 3 = 4(x)
y = 4x - 22
y - 3 = 4x
4x - y + 3 = 0