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3 years ago

Simplify the expression : l-8l + l8l

Mathematics

1 answer:

NikAS [45]3 years ago

6 0

16 it will be a positive number because it's the opposite of |-8| but it was -|8| then it would be a neg number

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Can someone let me know if I simplified these equations correctly or at least show me how to do it?

Grace [21]

Answer:

Your work is correct as far as it goes. Now eliminate the terms that are zero.

Step-by-step explanation:

Multiplying anything by zero gives zero. Adding zero is like adding nothing. Zero is called the "additive identity element" because ...

a + 0 = a

Adding zero doesn't change anything. You can (and should) drop the zero if your goal is to simplify the expression.

$a. \quad x_{f}=v_{0}\\\\b. \quad x_{f}=v_{0}t\\\\c. \quad v_{f}^2=v_{0}^2$

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3 years ago

What is the area of a triangle.

Firdavs [7]

Answer:

The area of a triangle is the base times height times 1/2. Please mark brainliest!!!!

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3 years ago

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What are the next three terms in the sequence 2, -4, -16, 32

Nikitich [7]

Answer:

128, -256, -1024

Step-by-step explanation:

multiply 32 by 4, multiply 128 by -2, multiply -256 by 4

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1 year ago

I need help on finding m

EastWind [94]

Answer:

39°

Step-by-step explanation:

$\angle RUS +\angle SUT = \angle RUT\\\\5x-4+3x+6 = 90\\\\8x+2=90\\\\8x=88\\\\x=11$

and now for SUT

$\angle SUT = 3(11)+6= 33+6 = 39$

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2 years ago

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Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

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3 years ago