Step-by-step explanation:
i hope this will help you
We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
The line is starting from right side and goes thorough left .
Means
- Its starts from 1st Quadrant and goes to 3rd Quadrant.(+ve to -ve)
- Y is infinite
Hence
The solution is
![\\ \sf\longmapsto (0,\infty]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%280%2C%5Cinfty%5D)
Answer:C
Step-by-step explanation:
length•width•height
12•4•5.5=264
