$\bf 5n^2+6n+7=n^2-4n\implies 5n^2+6n+7-n^2+4n=0
\\\\\\
4n^2+10n+7=0\\\\
-------------------------------\\\\
\begin{array}{llccll}
&{{ 4}}x^2&{{ +10}}x&{{ +7}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}$

if you get a positive value, that means 2 real solutions
if you get 0, means 1 real solution only
if you get a negative value, is an imaginary root solution, same as saying no solution.

4 0

3 years ago

It is monday. : there is chicken for lunch. write the inverse in if-then form. if it is monday, then there is chicken for lunch.

ololo11 [35]

If Monday, then Chicken
If no Chicken, then no Monday

3 0

4 years ago

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