Question

The equation of the line passing through the points (−10, 0) and (−8, 20) can be expressed as y = mx + b. Give the value of b.

Answer 1

First find slope:

20-0/-8+10= 20/2= 10

Slope=10

next use point slope form and solve it:

y-0=10(x+10)

y=10x+100

b=100

Answer 2

Given are the two points (-10,0) and (-8,20), and equation of the line as y=mx+b.

We can plug the given values in the equation as follows :-

0 = -10m + b .........equation(1)

20 = -8m + b .........equation(2)

Subtracting equation(1) from equation(2)

20 - 0 = (-8m + b) - (-10m + b)

20 = -8m + b + 10m - b

20 = 10m - 8m

20 = 2m

m = 10

Plugging m=10 in the equation(1)

0 = -10(10) + b

0 = -100 + b

b = 100

So final answer is b = 100.