All categories

3 years ago

Please help me with disss

Mathematics

1 answer:

Westkost [7]3 years ago

3 0

Answer:

-4

Step-by-step explanation:

You might be interested in

What is the value of x + y(3 - x) when x = -5 and y = 3?

cestrela7 [59]

Answer:

E. 19

Step-by-step explanation:

Step 1: Plug in the x and y values mentioned:

-5 + 3(3 - (-5))=

Step 2: Distribute the three:

-5 + 9+15=

Simplify:

Hope this helped and plz mark as brainliest!

Luna G.

4 0

3 years ago

I WILL GIVE U BRIANLIEST THING!!!

Allisa [31]

Answer:

y=6x+5

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which of the following is equivalent to x^-1/2 1) -1/2x 2) -√x 3) 1/√x 4) -1/2x

irina [24]

Answer:

Option (3) is correct.

Step-by-step explanation:

We need to find the expression that is equivalent to $x^{-1/2}$ .

The property is : $x^{-a}=\dfrac{1}{x^a}$

Here, a = 1/2

So,

$x^{-1/2}=\dfrac{1}{x^{1/2}}$

We know that, $x^{1/2}=\sqrt{x}$

$\dfrac{1}{x^{1/2}}=\dfrac{1}{\sqrt{x} }$

So, $x^{-1/2}$ is equivalent to $\dfrac{1}{\sqrt{x} }$

Hence, the correct option is (3).

3 0

3 years ago

Someone help please

fiasKO [112]

It is 4pi/7, or b. Just want to help ;)

4 0

2 years ago

In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales

mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The sample size and the estimate are given by:

$n = 161, \pi = \frac{37}{161} = 0.2298$

Hence:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 - 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.1648$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 + 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.2948$

The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

More can be learned about the z-distribution at brainly.com/question/25890103

5 0

2 years ago