can someone help me we out
Step-by-step explanation:
∫₀³⁰ (r/V C₀ e^(-rt/V)) dt
If u = -rt/V, then du = -r/V dt.
∫ -C₀ e^u du
-C₀ ∫ e^u du
-C₀ e^u + C
-C₀ e^(-rt/V) + C
Evaluate between t=0 and t=30.
-C₀ e^(-30r/V) − -C₀ e^(-0r/V)
-C₀ e^(-30r/V) + C₀
C₀ (-e^(-30r/V) + 1)
I got the same answer. Try changing the lowercase v to an uppercase V.
The number is -30
Exp
2/3=-20
1/3=-10
3/3=-30
X + x + 2 + x + 4 = -213
3x + 6 = -213
3x = -219
x = -73
-73 + 2 = -71
-73 + 4 = -69
Solution: -73, -71, -69
Answer:
32
Step-by-step explanation:
If you already have an angle of 148 on the arc TU, then 180-148=32
