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nadya68 [22]
3 years ago
7

Professional photographers often use the lowest quality settings on their cameras since this can be reversed in Photoshop.

Computers and Technology
2 answers:
Zanzabum3 years ago
7 0

Answer:

The correct answer is FALSE

kap26 [50]3 years ago
3 0
False you want to use the best lenses and settings as very fine details can't be edited plus let's be real no one wants to sit for three hours editing one photo 
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Designing, producing, exhibiting, performing, writing, and publishing multimedia content including visual and performing arts an
loris [4]
<span>arts, audio-video technology & communications</span>
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3 years ago
You have purchased a printer that has the capability to print in duplex mode so that users can print on both sides of a sheet of
fiasKO [112]

If you have purchased a printer that has the capability to print in duplex mode so that users can print on both sides of a sheet of paper. However, when users try to use this capability when they send a print job, documents are still printed on only one side. Then there might be a problem with (d) THE DUPLEX MODE NEEDS TO BE ENABLED ON THE DEVICE SETTINGS TAB IN THE PRINTER'S PROPERTIES.

Explanation:

  • If the duplex mode isn't enable on the printer setting, then the printer is still going to read that the output should come in a single page and not in the duplex mode.
  • When facing such a problem, the user should go to the "Device Settings" tab in the printer properties and change the required settings to print according to the users needs.

7 0
3 years ago
What would 128 kbps look like on a phone? i.e. 4g, 3g, 2g, etc
vovangra [49]
5g I think.............
8 0
3 years ago
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
3 years ago
Computer programming
Svet_ta [14]
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2 years ago
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