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kobusy [5.1K]
3 years ago
9

A jar contains 17 orange, 7 pink, and 4 black marbles. A marble is drawn at random. What is the probability that the marble is p

ink or orange?
A. 6⁄7

B. 24⁄31

C. 4⁄7

D. 1⁄6

E. 1⁄7
Mathematics
2 answers:
MakcuM [25]3 years ago
8 0

<em>Total amount of marbles:</em>

17 + 7 + 4 = 17 + 11 = 28

<em>Amount of marbles that are either orange or pink:</em>

17 + 7 = 24

To find the probability that the marble is pink or orange, we divide the amount of orange and pink marbles by the total amount:

P = 24/28 = 6/7

So the answer is A. 6/7

Elena L [17]3 years ago
4 0

Answer:6/7


Step-by-step explanation:  

total 17 +7+4=28

<u>what u want</u> =17+7=24

all you have =28

24/28=12/14=6/7

so your answer is 6/7




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An average orange weighs of 3/5 a pound. Based on this average, how many oranges are in six pounds of oranges? When you express
Ivan

Answer:  There are 10 oranges in 6 pounds.

When we express the problem as division problem, the number 6 is dividend.


Step-by-step explanation:

The average weight of one orange = \frac{3}{5} pounds

Therefore the number of oranges in 6 pounds=6\div \frac{3}{5}

⇒ The number of oranges in 6 pounds=6\times\frac{5}{3}

⇒ The number of oranges in 6 pounds=10

In the above division problem , the number 6 is the dividend.

3 0
2 years ago
A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop
Helen [10]

Answer:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

But we need to calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_I}{n}

And replacing we got:

\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072

And for the sample variance we have:

s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance \sigma^2

E(s^2) = \sigma^2

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

But we need to calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_I}{n}

And replacing we got:

\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072

And for the sample variance we have:

s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance \sigma^2

E(s^2) = \sigma^2

3 0
3 years ago
The scale on a map is stated as 1:250000 two villages are 7 cm apart on the map. How far from each other are the two villages in
a_sh-v [17]

Answer: 1750000

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4 0
2 years ago
How to simplify expressions
Volgvan
You gather the like terms together.
if you have -3y +2x +6w -4 + 3y -5x +2w

you put the like terms together
so for the term y:

you have -3y +3y = 0

for x:

2x - 5x = -2x

for w:

6w + 2w = +8w

and you also had -4. if you put them together you get

0 -2x +8w -4
which is

-2x +8w -4

hope this helps
8 0
3 years ago
Kohl's sells casual shirts for $9 and Poles shirts for $18. Total sales $1080, and customers bought 4 times as many casual as po
lbvjy [14]
If we assume the number of polo shirts have been sold is x, the number of casual shirts have been sold will be 4x.
x*18+4x*9=$1080
(18+36)x=$1080
54x=$1080
x=20

The number of casual shirts have been sold is 4*20=80

6 0
3 years ago
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