<span>statements is not true
</span><span>D. -a = c
-a should be equal d, not c</span>
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
a) 7
b) -8.2
c) 0
d) -7
e) -1 3/4
f) 121
Step-by-step explanation:
Just put the opposite for each one. The absolute value is the distance away from 0.
Answer:
The distributive property of multiplication
Step-by-step explanation:
we know that
The <u>distributive property of multiplication</u> states that the product of a number by a sum, is equal to multiply each addend by the number (This is called distributing the number) and then, you can add the products
so
in this problem we have
----> the number -3 is distributed
therefore
We have the distributive property of multiplication
Answer:
B. 0.20 per century
Step-by-step explanation:
I calculated it logically
