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anastassius [24]
3 years ago
15

Which expression is equivalent to (3x-1) (-5x+6)?

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

−15x2+23x−6

Step-by-step explanation:

(3x−1)(−5x+6)

=(3x+−1)(−5x+6)

=(3x)(−5x)+(3x)(6)+(−1)(−5x)+(−1)(6)

=−15x2+18x+5x−6

=−15x2+23x−6

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Mary has $6,000 saved for her college education. She invested that money at 2.3% interest per year. Suppose her account earned i
igomit [66]

Answer:

Interest= $423.59

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $6,000

Number of periods (n)= 3 years

Interest rate (i)= 2.3% = 0.023

<u>To calculate the Future Value, we need to use the following formula:</u>

FV= PV*(1+i)^n

FV= 6,000*(1.023^3)

FV= $6,423.59

<u>Now, the interest earned:</u>

<u />

Interest= 6,423.59 - 6,000

Interest= $423.59

8 0
2 years ago
What are the steps involved in the financial planning process?
rosijanka [135]

Answer:

determine current financial situation

develop your financial goals

identify alternative course of action

evaluate alternatives

Create and implement your financial action plan

review and revise the financial plan.

Hope this helps have a great day! btw I have a question plz help me its due tonight.

5 0
2 years ago
n the expression 5x6 + 3xy − 7yz2 + , which of the following choices is the exponent in the term 5x6?
astra-53 [7]

Answer:

7yz2+

Step-by-step explanation:

3 0
3 years ago
The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and
antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.25, \sigma = 0.05

a. What is the probability that a single car of this model fails to meet the NOX requirement?

Emissions higher than 0.3, which is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.3 - 0.25}{0.05}

Z = 1

Z = 1 has a pvalue of 0.8417.

1 - 0.8413 = 0.1587.

15.87% probability that a single car of this model fails to meet the NOX requirement.

b. A company has 4 cars of this model in its fleet. What is the probability that the average NOX level of these cars are above 0.3 g/mi limit?

Now we have n = 4, s = \frac{0.05}{\sqrt{4}} = 0.025

The probability is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3 - 0.25}{0.025}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

4 0
3 years ago
Combine like terms of<br><br> −5.8c+4.2−3.1+1.4c
Mars2501 [29]
You have to combine -5.8c+1.4c which = -4.4c
 then
combine 4.2-3.1 which = 1.1 
so the answer is 
-4.4c+1.1 or you can switch the numbers around 
6 0
3 years ago
Read 2 more answers
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