Answer:
The last one
Step-by-step explanation:
Let XXX and YYY be the following sets: X = \{9, 25\}X={9,25}X, equals, left brace, 9, comma, 25, right brace Y = \{1, 4, 9,16,25
Dmitry_Shevchenko [17]
Answer:
The answer is "
"
Step-by-step explanation:
Given value:
When we subtract set X - Y it means, that it will give only, that value which is not available on the set Y.
F(g(x)) = f(3x+2) = h(x)=9x^2+12x + 6
Note that (3x+2)^2 = 9x^2 + 12x + 4, which is almost, but not quite, equal to h(x).
Let's experiment. What if f(x) = x^2 + 2?
Then f(3x+2) = (3x+2)^2 + 2 = 9x^2 + 12x + 4 + 2 = 9x^2 + 12x + 6, which is the same as the given h(x).
Thus, f(x) is x^2 + 2.
I believe it would be -6.9♀️
For this case what we must do is define h (x), which is given by:
h (x) = f (x) * g (x)
Where,
f (x) = 5 (The number of fish breeding farms)
g (x) = 80 (1.04) ^ x (The approximate number of fish per breeding farm)
Substituting we have:
h (x) = (5) * (80 (1.04) ^ x)
Rewriting we have:
h (x) = 400 (1.04) ^ x
Answer:
the approximate population of the fish across all Mr. Dawson's farms after x months is:
h (x) = 400 (1.04) ^ x
