Answer: 2 vertices
The two vertices in question are (2,0) and (5,0). These are points A and D. These two points are on the x axis, which is the line of reflection. Any point on a line of reflection does not move.
The points (0,-3) and (3,-3) are not on the line of reflection, so they do move and are reflected to another location. Refer to the diagram below.
Problems of this sort are frequently found in physics. If you study calculus or physics you'll learn how to create the equation representing the velocity of an object in flight.
Here, you don't need to calculate velocity, but rather time. Start with this equation:
v = v0 + a t^2, where v is the velocity at time t, v0 is the initial velocity, a is the acceleration due to gravity (denoted by g instead of a), and t is the elapsed time.
You are told that v0 is 15 ft/sec. Set v = to 0, as the ball stops moving for the tiniest instant at the top of its trajectory. Use g = - 32 ft (per second squared).
Then 0 = 15 ft/sec - 32 [ft/(seconds squared)] t.
Solve this for t. This is the time required for the ball to come to a complete stop at the top of its trajectory.
Finally, multiply this time by 2, since the ball begins to fall and returns to its original height.
A. Will most likely be the answer I might be wrong.
2y+12 < 42
subtract 12 from both sides to isolate the 'y'
2y<30
since '2y' is multiplication, the opposite is division. divide by 2 to isolate the 'y'. doing so will flip the < sign to make it >.
y > 15
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She makes $15 an hour. Her employers take out $125 weekly. She gets a paycheck for $205 that week.
Add the $125 back in that her employer took out and you can find how much she earned that week, it's $330. Divide $330 by $15 to find that she worked a minimum of 22 hours that week.
15h-125=205
15h=330
h=22
plug 22 in to the equation 15h-125=205 to check your answer
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I can't help you with the last one. Best of luck though man and god bless.
Well for the first one you have to subtract 3 on both sides so that would make the equation x > -8 (because a negative subtracting a positive is basically a negative plus negative) and so your equations done. For the second one you divide both ides by -4 so your equation would be x < 4 (the sign would be less then or qual to because you divided by a negative)
