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In-s [12.5K]
4 years ago
13

What is $7.50 admission; 20% off; 5.75% tax

Mathematics
2 answers:
son4ous [18]4 years ago
8 0
7.50 divided by 5, is 1.50 off the admission that is 20% off then $7.50-1.50= $6 then you do 6 divided by 100= 0.06 x 5.75 % tax you add together total will be $6.35 the answer.
Dvinal [7]4 years ago
4 0

Hello, the answer you are looking for is $6.35. To get the answer, first do 7.50 divided by 5, is 1.50 off the admission that is 20% off then $7.50-1.50= $6 then you do 6 divided by 100= 0.06 x 5.75 % tax you add together total will be $6.35 the answer.

I hope  you understand the steps I explain.

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Ilya [14]
BOIII get outta here
3 0
3 years ago
Read 2 more answers
How many 100 dollar bills make 2324 dollars
Nikolay [14]

Answer: 24 $100 bills, even though this will add up to more than 2324 dollars, it is the amount needed to cover the price

Step-by-step explanation: divide 2324 dollars by 100

4 0
3 years ago
a map has a scale of 2in: 6mi. if a two twons on a map is 10 in apart then how far apart are the real twons
Brilliant_brown [7]

Answer:  30 miles

Work Shown:

2 in : 6 mi

5*2 in : 5*6 mi

10 in : 30 mi

7 0
2 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
Example 1:
yawa3891 [41]

Answer:

Step-by-step explanation:

4 0
3 years ago
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