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3 years ago

What is $7.50 admission; 20% off; 5.75% tax

2 answers:

8 0

7.50 divided by 5, is 1.50 off the admission that is 20% off then $7.50-1.50= $6 then you do 6 divided by 100= 0.06 x 5.75 % tax you add together total will be $6.35 the answer.

Dvinal [7]3 years ago

4 0

Hello, the answer you are looking for is $6.35. To get the answer, first do 7.50 divided by 5, is 1.50 off the admission that is 20% off then $7.50-1.50= $6 then you do 6 divided by 100= 0.06 x 5.75 % tax you add together total will be $6.35 the answer.

I hope you understand the steps I explain.

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Read 2 more answers

20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by

scoundrel [369]

Answer:

Part a) $f(2)=1.57\ sec$

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) $2,165.43\ sec$

Step-by-step explanation:

Let

f(d) -----> the time in seconds it takes for an object to fall

d -----> distance in feet

we have

$f(d)=1.11\sqrt{d}$

Part a): Determine f(2) and explain what it represents

we know that

f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

For $d=2\ ft$

substitute in the function above and solve for f(2)

$f(2)=1.11\sqrt{2}$

$f(2)=1.57\ sec$

therefore

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}

What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft

The maximum height of the basin is 3,805,774 ft

Part c) How long would it take a rock to drop from the rim to the bottom of the basin?

we know that

The distance from the rim to the bottom of the basin is equal to the maximum height of the basin

$d=3,805,774\ ft$