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3 years ago

9

How do you find area of a triangle

2 answers:

musickatia [10]3 years ago

8 0

Area= 1/2 base*height

Tatiana [17]3 years ago

5 0

Bytheformula..... Base times height divided by 2.... you put Given base and given height on the top of the fraction . You multiply them and then divide it by 2....so simple!!!!

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HELP ASAP i need rest

Shkiper50 [21]

Answer:

A

Step-by-step explanation:

To know the distance between the two on a number line, we subtract both numbers from each other

Since the absolute value will give the same result irrespective of the number we used first, we can see that it is the first option that would give the needed results

This means that option A is our answer

5 0

3 years ago

A hike starts at an elevation of 30 meters below sea level and ends at a point 9500 meters higher than the start point. How high

denpristay [2]

You would be 9470 meters above sea level

8 0

4 years ago

Read 2 more answers

EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If

amm1812

Answer:

To Prove: $9e^x$ is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If $f(x) = 9e^x$ , then $f ^{(n + 1)(x)} =9e^x$ for all n. If d is any positive number and |x| ≤ d, then $|f^{(n + 1)(x)}| = 9e^x\leq 9e^d.$

So Taylor's Inequality, with a = 0 and M = $9e^d$ , says that $|R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq d.$

Notice that the same constant $M = 9e^d$ works for every value of n.

But, since $lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$$ ,

We have $lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0$

It follows from the Squeeze Theorem that $lim_{n\to\infty} |R_n(x)|=0$ and therefore $lim_{n\to\infty} R_n(x)=0$ for all values of x.

$THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and $ lim_{n\to\infty} R_n(x)=0 \: for \: |x-a|$

By this theorem above, $9e^x$ is equal to the sum of its Maclaurin series, that is,

$9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}$ for all x.

6 0

3 years ago

If cos θ > 0, which quadrant(s) could the terminal side of θ lie?

Sergeeva-Olga [200]

Answer:

I and IV

Step-by-step explanation:

cosine is positive/greater than 0 in quadrants I and IV. Its just a rule of the unit circle.

Can remember by All Star Trig Class

meaning all the trig funtions are positive in quadrant I

sin is positive in II

tan is positive in III

and cos is positive in IV

8 0

3 years ago

3(x-1) - 8 = 4(1+x) +5

juin [17]

Answer:

x=-20

Step-by-step explanation:

3x-11=4x+9

3x=4x+20

x+20=0

x=-20

8 0

3 years ago

Read 2 more answers