Answer:
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)
y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Answer:
y = 1m - 1
Step-by-step explanation:
6/3 = 6 divided by 3
= 2
12/6= 12 divided by 6
= 2
Answer:
In each muffin there are 1.53oz
Step-by-step explanation:
The first step is to get the weight of just one muffin. If the package contains six muffins we must divide the total weight by six.
The weight of just one muffin is 3oz.
Now, the problem says that blueberry high-fiber muffins contain 51 % dietary fiber by mass, which means that we must calculate the 51% of 3oz. We must take into account that 51% equals 51/100 which is 0.51. The equation would be:
Finally, in each muffin there are 1.53oz of fiber.
