Answer:
15+15+15+2+2+2+2=(3×15)+(4×2)=45+8=53
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
I believe the correct answer is C) 30<span>°
If this is the right answer then please give a heart and rating so others can know!</span>
Answer:
1. Yes
2. No
3. No
4. No
5. Yes
Step-by-step explanation:
Do you mean equal proportion?
1. 3 : 9 = 6 : 18 TRUE because 3 : 9 = 1 : 3 and 6 : 18 = 1 : 3
2. 28 : 7 = 64 : 16 FALSE because they are just not related.
3. 95 : 100 = 17 : 20 FALSE because the closest they get are 19 : 20 ≠ 17 : 20
4. 60 : 80 = 14 : 16 FALSE because the closest they get are 60 : 80 = 6 : 8 and 14 : 16 = 7 : 8
5. 200 : 300 = 24 : 36 TRUE because 200 : 300 = 2 : 3 and 24 : 36 = 2 : 3
