Write it in y= mx+b form. Subtract 5x from both sides to get 4y = -5x + 100. Divide by 4 so the answer would be y= -5/4x + 25.
First, sum up the total expenses for the original plan
Duque de Caxias + Campinas + Rio de Janeiro + Guarulhos = 242+185+193+120 = R$740
It is clearly over the intended budget. The average cost per itinerary is around R$200 so we will consider making a swap on either Duque de Caxias and Rio de Janeiro. Possible answers are (b) or (c)
for (b) Replace Duque de Caxias with Fortaleza, we will have
Fortaleza + Campinas + Rio de Janeiro + Guarulhos =
⇒ 201+185+193+120 = R$699 ⇒ This is exactly the budget intended for the trip
for (C) Replace Rio de Janeiro with Porto Alegre
Duque de Caxias + Campinas + Porto Alegre + Guarulhos =
⇒ 242 + 185 + 153 +120 = R$ 700 ⇒ This is over R$1
The answer is (b)
Answer:
2500÷$3.21 =778.81
just round to the nearest whole number
(a^3-2a^2)-(3a^2-4a^3)
(a^3-2a^2)-3a^2+4a^3
5a^3-5a^2
Retrievers of baraka select 130 a random repair replacing the pump over the furnace and random reason
