Question

Find the area of the figure to the nearest tenth.

Answer 1

Look at the picture in the attachment.
The area of the figure is equal to the sum of the areas A₁ and A₂.

$A_1=9 \ mm \times 4.8 \ mm=43.2 \ mm^2 \\ A_2=\frac{9 \ mm \times 7.7 \ mm}{2}=\frac{69.3 \ mm^2}{2}=34.65 \ mm^2 \\ \\ A=43.2 \ mm^2 + 34.65 \ mm^2=77.85 \ mm^2 \approx 77.9 \ mm^2$

The answer is A.