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N76 [4]
3 years ago
12

What fraction is equivalent to 210/100 that is not improper​

Mathematics
1 answer:
Feliz [49]3 years ago
6 0
2 1/10 would be he correct answer
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Please help it's four am and I really hate math
tangare [24]

Answer:

A

Step-by-step explanation:

number books = n

2xn / 15

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3 years ago
Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Is this possible if he invests with a rate
Juli2301 [7.4K]
Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Question: Is this possible if he invests with a rate of return of 6%?We'll we are not sure with the answer unless we solve it. So let's start solving.=> 6% = 6% / 100% = 0.06Now, we have the value of 6% that will be multiplied with the amount to identify his annual interest rate:=> $4,200 * 0.06 = 252 dollars is his annual interest rateLet's multiply this for 4 years=> 252 dollars * 4 = 1008 dollarsThen, let's sum up:<span>=> $4,200 + 1008 dollars = 5 208 dollars.</span>
5 0
3 years ago
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Helpppp ????????????????
Nady [450]
The answer is 1 in 10 or 10%
7 0
3 years ago
Can anybody help me please
Alexus [3.1K]

Answer:

The answers follow in order, yes, no, and no.

Step-by-step explanation:

3 0
4 years ago
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Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
Aleonysh [2.5K]

Answer:

The only possible number is 80.

Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

  • 1 \times 40 < 55 = 1 \times 40 + 15, and
  • 2 \times 40 + 21 = 101 < 3 \times 40.

Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

5 0
4 years ago
Read 2 more answers
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